# pensim package user guide

#### Levi Waldron

#### December 06, 2022

# 1 Introduction

This package acts as a wrapper to the penalized R package to add the following functionality to that package:

- repeated tuning on different data folds, with parallelization to take advantage of multiple processors
- two-dimensional tuning of the Elastic Net
- calculation of cross-validated risk scores through a nested cross-validation procedure, with parallelization to take advantage of multiple processors

It also provides a function for simulation of collinear high-dimensional data with survival or binary response.

This package was developed in support of the study by Waldron et al. (2011).
This paper contains greater detail on proper application of the methods provided here. Please cite this paper when using the pensim package in your research, as well as the penalized package (Goeman (2010)).

# 2 Example data

pensim provides example data from a microarray experiment investigating survival of cancer patients with lung adenocarcinomas (Beer et al. (2002)). Load this data and do an initial pre-filter of genes with low IQR:

    library(pensim)
    data(beer.exprs)
    data(beer.survival)
    ##select just 100 genes to speed computation, just for the sake of example:
    set.seed(1)
    beer.exprs.sample <- beer.exprs[sample(1:nrow(beer.exprs), 100),]
    #
    gene.quant <- apply(beer.exprs.sample, 1, quantile, probs = 0.75)
    dat.filt <- beer.exprs.sample[gene.quant > log2(100),]
    gene.iqr <- apply(dat.filt, 1, IQR)
    dat.filt <- as.matrix(dat.filt[gene.iqr > 0.5,])
    dat.filt <- t(dat.filt)
    dat.filt <- data.frame(dat.filt)
    #
    library(survival)
    surv.obj <- Surv(beer.survival$os, beer.survival$status)

Note that the expression data are in “wide” format, with one column per predictor (gene). It is recommended to put covariate data in a dataframe object, rather than a matrix.

# 3 Nested cross-validation

Unbiased estimation of prediction accuracy involves two levels of cross-validation: an outer level for estimating prediction accuracy, and an inner level for model tuning. This process is simplified by the opt.nested.crossval function.

It is recommended first to establish the arguments for the penalized regression by testing on the penalized package functions `optL1` (for LASSO), `optL2` (for Ridge) or `cvl` (for Elastic Net). Here we use LASSO. Setting `maxlambda1=5` is not a generally recommended procedure, but is useful in this toy example to avoid converging on the null model.

    library(penalized)

    ## Warning: package 'penalized' was built under R version 4.2.2

    ## Welcome to penalized. For extended examples, see vignette("penalized").

    testfit <- optL1(
      response = surv.obj,
      penalized = dat.filt,
      fold = 5,
      maxlambda1 = 5,
      positive = FALSE,
      standardize = TRUE,
      trace = FALSE
    )

Now pass these arguments to `opt.nested.crossval()` for cross-validated calculation and assessment of risk scores, with the additional arguments:

- `outerfold` and `nprocessors`: number of folds for the outer level of cross-validation, and the number of processors to use for the outer level of cross-validation (see `?opt.nested.crossval`)
- optFUN and scaling: which optimization function to use (`opt1D` for LASSO or Ridge, `opt2D` for Elastic Net) - see `?opt.splitval`.
- setpen and nsim: setpen defines whether to do LASSO (“L1”) or Ridge (“L2”), `nsim` defines the number of times to repeat tuning (see `?opt1D`. `opt2D` has different required arguments.)

    set.seed(1)
    preds <-
      opt.nested.crossval(
        outerfold = 5,
        nprocessors = 1,
        #opt.nested.crossval arguments
        optFUN = "opt1D",
        scaling = FALSE,
        #opt.splitval arguments
        setpen = "L1",
        nsim = 1,
        #opt1D arguments
        response = surv.obj,
        #rest are penalized::optl1 arguments
        penalized = dat.filt,
        fold = 5,
        positive = FALSE,
        standardize = TRUE,
        trace = FALSE
      )

Ideally nsim would be 50, and outerfold and fold would be 10, but the values below speed computation 200x compared to these recommended values. Note that here we are using the `standardize=TRUE` argument of `optL1` rather than the `scaling=TRUE` argument of opt.splitval. These two approaches to scaling are roughly equivalent, but the scaling approaches are not the same (`scaling=TRUE` does z-score, `standardize=TRUE` scales to unit central L2 norm), and results will not be identical. Also, using `standardize=TRUE` scales variables but provides coeffients for the original scale, whereas using scaling=TRUE scales variables in the training set then applies the same scales to the test set.

## 3.1 Summarization and plotting

Cox fit on the continuous risk predictions:

    coxfit.continuous <- coxph(surv.obj~preds)
    summary(coxfit.continuous)

    ## Call:
    ## coxph(formula = surv.obj ~ preds)
    ##
    ##   n= 86, number of events= 24
    ##
    ##          coef exp(coef) se(coef)     z Pr(>|z|)
    ## preds 0.01639   1.01653  0.07769 0.211    0.833
    ##
    ##       exp(coef) exp(-coef) lower .95 upper .95
    ## preds     1.017     0.9837     0.873     1.184
    ##
    ## Concordance= 0.543  (se = 0.057 )
    ## Likelihood ratio test= 0.04  on 1 df,   p=0.8
    ## Wald test            = 0.04  on 1 df,   p=0.8
    ## Score (logrank) test = 0.04  on 1 df,   p=0.8

Dichotomize the cross-validated risk predictions at the median, for visualization:

    preds.dichot <- preds > median(preds)

Plot the ROC curve:

    nobs <- length(preds)
    cutoff <- 12
    if (requireNamespace("survivalROC", quietly = TRUE)) {
     preds.roc <-
      survivalROC::survivalROC(
        Stime = beer.survival$os,
        status = beer.survival$status,
        marker = preds,
        predict.time = cutoff,
        span = 0.01 * nobs ^ (-0.20)
      )
     plot(
      preds.roc$FP,
      preds.roc$TP,
      type = "l",
      xlim = c(0, 1),
      ylim = c(0, 1),
      xlab = paste("FP", "\n", "AUC = ", round(preds.roc$AUC, 3)),
      lty = 2,
      ylab = "TP",
      main = "LASSO predictions\n ROC curve at 12 months"
     )
     abline(0, 1)
    }

# 4 Getting coefficients for model fit on all the data

Finally, we can get coefficients for the model fit on all the data, for future use. Note that nsim should ideally be greater than 1, to train the model using multiple foldings for cross-validation. The output of `opt1D` or `opt2D` will be a matrix with one row per simulation. The default behavior in `opt.nested.crossval()` is to take the simulation with highest cross-validated partial log likelihood (CVL), which is the recommended way to select a model from the multiple simulations.

    beer.coefs <- opt1D(
      setpen = "L1",
      nsim = 1,
      response = surv.obj,
      penalized = dat.filt,
      fold = 5,
      maxlambda1 = 5,
      positive = FALSE,
      standardize = TRUE,
      trace = FALSE
    )

We can also include unpenalized covariates, if desired. Note that when keeping only one variable for a penalized or unpenalized covariate, indexing a dataframe like `[1]` instead of doing `[, 1]` preserves the variable name. With `[, 1]` the variable name gets converted to ““.

    beer.coefs.unpen <-
      opt1D(
        setpen = "L1",
        nsim = 1,
        response = surv.obj,
        penalized = dat.filt[-1],
        # This is equivalent to dat.filt[,-1]
        unpenalized = dat.filt[1],
        fold = 5,
        maxlambda1 = 5,
        positive = FALSE,
        standardize = TRUE,
        trace = FALSE
      )

Note the non-zero first coefficient this time, due to it being unpenalized:

    beer.coefs[1, 1:5]        #example output with no unpenalized covariates

    ##             L1            cvl    J04130_s_at U20758_rna1_at    L11672_r_at
    ##     4.99896033  -115.19258054     0.00000000     0.09998177    -0.10312924

    beer.coefs.unpen[1, 1:5]  #example output with first covariate unpenalized

    ##             L1            cvl    J04130_s_at U20758_rna1_at    L11672_r_at
    ##     4.99906823  -117.76317249    -0.15193598     0.10888431    -0.03394335

# 5 Simulation of collinear high-dimensional data with survival or binary outcome

The pensim also provides a convenient means to simulation high-dimensional expression data with (potentially censored) survival outcome or binary outcome which is dependent on specified covariates.

## 5.1 Binary outcome example

First, generate the data. Here we simulate 20 variables. The first 15 (group “a”) are uncorrelated, and have no association with outcome. The final five (group “b”) have covariance of 0.8 to each other variable in that group. The response variable is associated with the first variable group “b” (`firstonly=TRUE`) with a coefficient of 2.

Binary outcomes for \(n_s= 50\) samples are simulated as a Bernoulli distribution with probability for patient s:

\[\begin{equation} p_{s} =\frac{1}{1 + exp(-\beta X_{s})} \end{equation}\]

with \(\beta_{s,16} = 0.5\) and all other \(\beta_{s,i}\) equal to zero.

The code for this simulation is as follows:

    set.seed(9)
    x <- create.data(
      nvars = c(15, 5),
      cors = c(0, 0.8),
      associations = c(0, 2),
      firstonly = c(TRUE, TRUE),
      nsamples = 50,
      response = "binary",
      logisticintercept = 0.5
    )

Take a look at the simulated data:

    summary(x)

    ##              Length Class      Mode
    ## summary        6    data.frame list
    ## associations  20    -none-     numeric
    ## covariance   400    -none-     numeric
    ## data          21    data.frame list

    x$summary

    ##   start end cors associations num firstonly
    ## a     1  15  0.0            0  15      TRUE
    ## b    16  20  0.8            2   5      TRUE

A simple logistic model fails at variable selection in this case:

    simplemodel <- glm(outcome ~ ., data = x$data, family = binomial)

    ## Warning: glm.fit: algorithm did not converge

    ## Warning: glm.fit: fitted probabilities numerically 0 or 1 occurred

    summary(simplemodel)

    ##
    ## Call:
    ## glm(formula = outcome ~ ., family = binomial, data = x$data)
    ##
    ## Deviance Residuals:
    ##        Min          1Q      Median          3Q         Max
    ## -8.155e-05  -2.100e-08   2.100e-08   2.100e-08   7.017e-05
    ##
    ## Coefficients:
    ##               Estimate Std. Error z value Pr(>|z|)
    ## (Intercept)    146.045  28566.445   0.005    0.996
    ## a.1            205.225  36863.342   0.006    0.996
    ## a.2           -350.824  60613.163  -0.006    0.995
    ## a.3             26.278   9549.552   0.003    0.998
    ## a.4           -221.866  39113.234  -0.006    0.995
    ## a.5             95.717  24911.161   0.004    0.997
    ## a.6             36.924  12817.964   0.003    0.998
    ## a.7           -246.090  44715.891  -0.006    0.996
    ## a.8             65.058  13128.095   0.005    0.996
    ## a.9           -316.993  58214.882  -0.005    0.996
    ## a.10             4.299  20688.797   0.000    1.000
    ## a.11          -218.757  39199.270  -0.006    0.996
    ## a.12            63.066  20305.078   0.003    0.998
    ## a.13            54.937  11733.007   0.005    0.996
    ## a.14          -112.590  30198.194  -0.004    0.997
    ## a.15           398.687  74940.068   0.005    0.996
    ## b.1            498.778  88875.945   0.006    0.996
    ## b.2           -297.858  56626.061  -0.005    0.996
    ## b.3           -677.344 116466.624  -0.006    0.995
    ## b.4            188.575  39169.971   0.005    0.996
    ## b.5            699.090 123792.675   0.006    0.995
    ##
    ## (Dispersion parameter for binomial family taken to be 1)
    ##
    ##     Null deviance: 6.5342e+01  on 49  degrees of freedom
    ## Residual deviance: 6.6338e-08  on 29  degrees of freedom
    ## AIC: 42
    ##
    ## Number of Fisher Scoring iterations: 25

But LASSO does a better job, selecting several of the collinear variables in the “b” group of variables which are associated with outcome:

    lassofit <-
      opt1D(
        nsim = 3,
        nprocessors = 1,
        setpen = "L1",
        penalized = x$data[1:20],
        response = x$data[, "outcome"],
        trace = FALSE,
        fold = 10
      )
    print(lassofit)

    ##            L1       cvl (Intercept) a.1 a.2 a.3 a.4 a.5 a.6 a.7 a.8 a.9 a.10
    ## [1,] 3.436910 -27.56252   0.6389925   0   0   0   0   0   0   0   0   0    0
    ## [2,] 4.167477 -27.70431   0.6255205   0   0   0   0   0   0   0   0   0    0
    ## [3,] 3.949795 -28.37533   0.6291330   0   0   0   0   0   0   0   0   0    0
    ##      a.11 a.12 a.13 a.14      a.15       b.1 b.2 b.3 b.4 b.5
    ## [1,]    0    0    0    0 0.0128977 0.9981297   0   0   0   0
    ## [2,]    0    0    0    0 0.0000000 0.8915954   0   0   0   0
    ## [3,]    0    0    0    0 0.0000000 0.9227009   0   0   0   0

And visualize the data as a heatmap:

    dat <- t(as.matrix(x$data[,-match("outcome", colnames(x$data))]))
    heatmap(dat, ColSideColors = ifelse(x$data$outcome == 0, "black", "white"))

Figure 2: Heatmap of simulated data with binary response.

## 5.2 Survival outcome example

We simulate these data in the same way, but with `response="timetoevent"`. Here censoring is uniform random between times 2 and 10, generating approximately 34% censoring:

    set.seed(1)
    x <- create.data(
      nvars = c(15, 5),
      cors = c(0, 0.8),
      associations = c(0, 0.5),
      firstonly = c(TRUE, TRUE),
      nsamples = 50,
      censoring = c(2, 10),
      response = "timetoevent"
    )

How many events are censored?

    sum(x$data$cens == 0) / nrow(x$data)

    ## [1] 0.42

Kaplan-Meier plot of this simulated cohort:

    library(survival)
    surv.obj <- Surv(x$data$time, x$data$cens)
    plot(survfit(surv.obj ~ 1), ylab = "Survival probability", xlab = "time")

Figure 3: Kaplan-Meier plot of survival of simulated cohort.

# 6 Session Info

    sessionInfo()

    ## R version 4.2.1 (2022-06-23)
    ## Platform: x86_64-pc-linux-gnu (64-bit)
    ## Running under: Ubuntu 20.04.4 LTS
    ##
    ## Matrix products: default
    ## BLAS:   /usr/lib/x86_64-linux-gnu/openblas-pthread/libblas.so.3
    ## LAPACK: /usr/lib/x86_64-linux-gnu/openblas-pthread/liblapack.so.3
    ##
    ## locale:
    ##  [1] LC_CTYPE=en_US.UTF-8       LC_NUMERIC=C
    ##  [3] LC_TIME=en_US.UTF-8        LC_COLLATE=C
    ##  [5] LC_MONETARY=en_US.UTF-8    LC_MESSAGES=en_US.UTF-8
    ##  [7] LC_PAPER=en_US.UTF-8       LC_NAME=C
    ##  [9] LC_ADDRESS=C               LC_TELEPHONE=C
    ## [11] LC_MEASUREMENT=en_US.UTF-8 LC_IDENTIFICATION=C
    ##
    ## attached base packages:
    ## [1] stats     graphics  grDevices utils     datasets  methods   base
    ##
    ## other attached packages:
    ## [1] penalized_0.9-52 survival_3.3-1   pensim_1.3.6
    ##
    ## loaded via a namespace (and not attached):
    ##  [1] Rcpp_1.0.9      knitr_1.39      magrittr_2.0.3  MASS_7.3-58.1
    ##  [5] splines_4.2.1   lattice_0.20-45 R6_2.5.1        rlang_1.0.4
    ##  [9] fastmap_1.1.0   highr_0.9       stringr_1.4.0   tools_4.2.1
    ## [13] parallel_4.2.1  grid_4.2.1      xfun_0.31       cli_3.3.0
    ## [17] jquerylib_0.1.4 htmltools_0.5.3 yaml_2.3.5      digest_0.6.29
    ## [21] Matrix_1.4-1    sass_0.4.4      cachem_1.0.6    evaluate_0.15
    ## [25] rmarkdown_2.18  stringi_1.7.8   compiler_4.2.1  bslib_0.4.1
    ## [29] jsonlite_1.8.0

# References

Beer, David G., Sharon L.R. Kardia, Chiang-Ching Huang, Thomas J. Giordano, Albert M. Levin, David E. Misek, Lin Lin, et al. 2002. “Gene-Expression Profiles Predict Survival of Patients with Lung Adenocarcinoma.” Nat Med 8 (8): 816–24. https://doi.org/10.1038/nm733.
Goeman, Jelle J. 2010. “L1 Penalized Estimation in the Cox Proportional Hazards Model.” Biometrical Journal. Biometrische Zeitschrift 52 (1): 70–84. https://doi.org/10.1002/bimj.200900028.
Waldron, Levi, Melania Pintilie, Ming-Sound Tsao, Frances A Shepherd, Curtis Huttenhower, and Igor Jurisica. 2011. “Optimized Application of Penalized Regression Methods to Diverse Genomic Data.” Bioinformatics 27 (24): 3399–3406. https://doi.org/10.1093/bioinformatics/btr591.